# Verify if the equation log2 (x)=-1 have solutions?

### 1 Answer | Add Yours

First, we'll take antilogarithm, to determine x. In this case, this means to raise the given base of logarithm, namely 2, to the power -1.

log2 (x) = -1 => x = 2^-1

We'll use the negative power property:

2^-1 = 1/2

x = 1/2

Since x>0, then 1/2 represents the solution of the equation.

**Therefore, the given equation has one solution x = 1/2.**