# verify: cos(theta) + tan(theta) x Sin(theta) = Sec(theta)

*print*Print*list*Cite

### 3 Answers

The least common denominator is cos theta, so I multilplied

`[costheta]/1=[costheta*costheta]/[1*costheta]`

`costheta+tantheta*sintheta=`

`costheta+[sintheta]/[costheta]*sintheta=`

`[costheta*costheta]/[costheta]+[sin^2(theta)]/[costheta]=`

`[cos^2theta+sin^2theta]/costheta=`

`1/[costheta]=sectheta`

can you explain the 3rd part