verify: cos(theta) + tan(theta) x Sin(theta) = Sec(theta)

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rcmath | High School Teacher | (Level 1) Associate Educator

Posted on

The least common denominator is cos theta, so I multilplied 

`[costheta]/1=[costheta*costheta]/[1*costheta]`

 

 

rcmath's profile pic

rcmath | High School Teacher | (Level 1) Associate Educator

Posted on

`costheta+tantheta*sintheta=`

`costheta+[sintheta]/[costheta]*sintheta=`

`[costheta*costheta]/[costheta]+[sin^2(theta)]/[costheta]=`

`[cos^2theta+sin^2theta]/costheta=`

`1/[costheta]=sectheta`

 

 

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therockyhorror | Student, Undergraduate | (Level 1) eNoter

Posted on

can you explain the 3rd part

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