Vectors as forces question: A 10 kg block lies on a smooth ramp that is inclined at 30 degrees... A 10 kg block lies on a smooth ramp that is inclined at 30 degrees. What force, parallel to the ramp, would prevent the block from moving? (Assume that 1 kg exerts a force of 9.8 N)
- print Print
- list Cite
Expert Answers
Luca B.
| Certified Educator
calendarEducator since 2011
write5,348 answers
starTop subjects are Math, Science, and Business
You need to figure out what are the forces acting on the block. The gravity force acts on the block and it is orthogonal to horizontal axis.
The gravity vector makes an angle of `30^o` to the normal axes to inclined ramp, that passes through centroid of the body.
You need to find horizontal component of gravity force vector, such that:
`F_x = G*cos 60^o`
`F_x = 10*9.8*(1/2)`
`F_x = 49 N`
Hence, evaluating the force that stops the body to move, neglecting the friction force, yields `F_x = 49 N` .
Related Questions
- How much force does the 4 kg block exert on the 6.0 kg block and how much force does the 4 kg...
- 1 Educator Answer
- A 20 kg block lies on a ramp inclined at 35. What is the force, would prevent the block from...
- 1 Educator Answer
- A box sits on a ramp that is inclined at 42 degrees. The force of gravity on the box is 200N.If...
- 1 Educator Answer
- A 200 g hockey puck is launched up a metal ramp that is inclined at a 30° angle. The...
- 1 Educator Answer
- A skateboarding ramp rises from the ground at a 30o angle. If the ramp covers 20 feet on the...
- 1 Educator Answer