The vapor density of a gas is 11.2. The volume occupied by 10 g of the gas at STP is?
The molar mass of a gas, given the vapor density is calculated as:
molar mass = 2 x vapor density
The vapor density of the gas is 11.2. Thus, the molar mass of the gas is:
molar mass = 2 x 11.2 = 22.4 gm/mole
The given amount of the gas is 10 gm. Thus the number of moles of the gas are:
Number of moles = 10/22.4 mole = 0.45 moles (approximately)
At STP, 1 mole of a gas occupies 22.4 lt of volume. Here, we have about 0.45 moles of the gas. Hence the volume occupied by the gas at STP is:
Volume occupied = 0.45 x 22.4 lt = 10 lt.
Thus, the 10 gm of a gas, with a vapor density of 11.2, will occupy 10 lt of volume at STP.
Hope this helps.
check Approved by eNotes Editorial