If `v` is an eigenvector of `A` with corresponding eigenvalue `lambda` and `c` is a scalar, show that `v` is an eigenvector of `A-cI` with corresponding eigenvalue `lambda-c.`
I'm not sure where to start here.
1 Answer | Add Yours
Just start from what you're given and the definitions. Since `v` is an eigenvector of `A` with eigenvalue `lambda` , we have
For `v` to be an eigenvector of `A-cI` with eigenvalue `lambda-c,` this would mean that
`(A-cI)v=(lambda-c)v.` This isn't too hard to show:
where the first equality is true by linearity and the second is true by the definition of `I` and because we're told that ```Av=lambda v.`
We’ve answered 319,206 questions. We can answer yours, too.Ask a question