If `v` is an eigenvector of `A` with corresponding eigenvalue `lambda` and `c` is a scalar, show that `v` is an eigenvector of `A-cI` with corresponding eigenvalue `lambda-c.` I'm not sure where to...
If `v` is an eigenvector of `A` with corresponding eigenvalue `lambda` and `c` is a scalar, show that `v` is an eigenvector of `A-cI` with corresponding eigenvalue `lambda-c.`
I'm not sure where to start here.
- print Print
- list Cite
Expert Answers
degeneratecircle
| Certified Educator
calendarEducator since 2012
write290 answers
starTop subject is Math
Just start from what you're given and the definitions. Since `v` is an eigenvector of `A` with eigenvalue `lambda` , we have
`Av=lambda v.`
For `v` to...
(The entire section contains 82 words.)
Unlock This Answer Now
Start your 48-hour free trial to unlock this answer and thousands more. Enjoy eNotes ad-free and cancel anytime.
Related Questions
- Find the eigenvalues and eigenvectors of A geometrically. Where A=[0110] (a reflection in the...
- 1 Educator Answer
- A is nxn Matrix M(R) and lambda is a number in R such that lambda^2is an eigenvalue of A^2. Can...
- 2 Educator Answers
- Give an example of a non-diagonalizable 4x4 matrix with eigenvalues: -1, -1, 1, 1.
- 1 Educator Answer
- Prove that (cA)^-1=(1/c)A^-1If A is an invertible matrix and c is a nonzero scalar, then cA is an...
- 1 Educator Answer