# using y -3 = 3(x + 1) what is he equation form of a parallel line that passes through 0, -2 ? on the parallel line, what is the ordered pair wehre x = -2? show all steps

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The equation of a line parallel to the line y - 3 = 3(x + 1) and passing through the point (0, -2) has to be determined.

Two parallel lines have equal slope. The line y - 3 = 3(x +1) in slope intercept form is:

y - 3 = 3x + 3

=> y = 3x + 6

The equation of a parallel line passing through (0, -2) is `(y +2)/(x -0) = 3`

=> y + 2 = 3x

=> 3x - y - 2 = 0

At the point where x = -2, y = 3*(-2) - 2 = -8

**The equation of the line parallel to y - 3 = 3(x+1) and passing through (0, -2) is 3x - y - 2 = 0. The ordered pair where x = -2 is (-2, -8)**

The equation of the original line is y -3 = 3(x + 1). Representing this in the form y = mx + c

y - 3 = 3x + 3

y = 3x + 6

The slope of this line is 3.

Parallel lines have the same slope.

The equation of a line parallel to y -3 = 3(x + 1) and passing through (0, -2) is (y + 2)/(x - 0) = 3

y + 2 = 3x

At the point where x = -2, y = -6 - 2 = -8