Using only the numbers 1 2 3 and 4 write numerical expressions to equal 27, 34, 38, 42, 43, 44, and 47 ! Ex. 1 + 2 + 3 + 4 =10 Ex. 3^2 + 4 - 1 = 10
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There are an infinite number of ways to accomplish this task, but I'll use a slightly different approach for each number.
- 27 Exponents: 3^3
- 34 Multiplication and Addition: 4x4 + 4x4 + 2
- 38 Addition and Subtraction: 4 + 4 + 4 + 4 + 4 + 4 + 4 + 4 + 4 + 4 -2
- 42 Multiplication and Subtraction: 4x4x3 - 4 - 2
- 43 Exponents, Division, Subtraction: ((4^4 / 2) + 1) / 3
- 44 Multiplication and Addition: (4 + 4 + 3) x 4
- 47 Exponents and Subtraction: 4^3 - 2^4 - 1
...or do you mean you can only use each of these four digits once?
(23+4) x 1 = 27
34 x (1^2) = 34
42 - 3 - 1 = 38
42 x (1^3) = 42
43 x (1^2) = 43
43 + (1^2) = 44
41 + (3x2) = 47
I know that this is a little on the lateral thinking side, but perhaps it qualifies too.
It isn't clear in the question whether you need to use all 4 of the numbers in each or if you can combine the numbers to make a two-digit number, but either way there are several combinations you can use to accomplish this. These are just some of the ways you can get the answer.
3^3=27
33+1=34
42-4=38
34+(4*2)=42
34+(4*2)+1=43
4*11=44
(3^3)+(4^2)+4=47
23 + (4/1) = 27
34 / 1^2 = 34
42 - 3 - 1 = 38
42 x 1^3 = 42
42 + 1^3 = 43
43 + 1^2 = 44
41 + 2x3 = 47