Using only the numbers 1 2 3 and 4 write numerical expressions to equal 27, 34, 38, 42, 43, 44, and 47 ! Ex. 1 + 2 + 3 + 4 =10 Ex. 3^2 + 4 - 1 = 10

4 Answers | Add Yours

aespinoza71's profile pic

aespinoza71 | (Level 1) Adjunct Educator

Posted on

...or do you mean you can only use each of these four digits once?

(23+4) x 1 = 27

34 x (1^2) = 34

42 - 3 - 1 = 38

42 x (1^3) = 42

43 x (1^2) = 43

43 + (1^2) = 44

41 + (3x2) = 47

I know that this is a little on the lateral thinking side, but perhaps it qualifies too.

caledon's profile pic

caledon | High School Teacher | (Level 3) Senior Educator

Posted on

There are an infinite number of ways to accomplish this task, but I'll use a slightly different approach for each number.

  • 27  Exponents: 3^3
  • 34  Multiplication and Addition: 4x4 + 4x4 + 2
  • 38  Addition and Subtraction: 4 + 4 + 4 + 4 + 4 + 4 + 4 + 4 + 4 + 4 -2
  • 42  Multiplication and Subtraction: 4x4x3 - 4 - 2
  • 43  Exponents, Division, Subtraction: ((4^4 / 2) + 1) / 3
  • 44  Multiplication and Addition: (4 + 4 + 3) x 4
  • 47  Exponents and Subtraction: 4^3 - 2^4 - 1
rachellopez's profile pic

rachellopez | Student, Grade 12 | (Level 1) Valedictorian

Posted on

It isn't clear in the question whether you need to use all 4 of the numbers in each or if you can combine the numbers to make a two-digit number, but either way there are several combinations you can use to accomplish this. These are just some of the ways you can get the answer.

3^3=27

33+1=34

42-4=38

34+(4*2)=42

34+(4*2)+1=43

4*11=44

(3^3)+(4^2)+4=47

glendamaem's profile pic

glendamaem | Student | (Level 1) Honors

Posted on

23 + (4/1)  = 27

34 / 1^2    = 34

42 - 3 - 1  = 38

42 x 1^3   = 42

42 + 1^3  = 43

43 + 1^2  = 44

41 + 2x3  = 47

We’ve answered 318,915 questions. We can answer yours, too.

Ask a question