# Using the method of trigonometric show your users that ∫ dx/√(x^2+2x) = In |x + 1 + √(x^2+2x)| + constant

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You should complete the square to denominator using the following formula such that:

`(a+b)^2 = a^2 + 2ab + b^2`

`x^2 + 2x = a^2 + 2ab => {(x^2=a^2 => a=x),(2x = 2xb => b=1):}`

Hence, you need to add 1 to complete the square and subtract 1 to preserve the equation such that:

`x^2 + 2x + 1 - 1 = (x + 1)^2 - 1`

Hence, substituting `(x + 1)^2 - 1`  for `x^2 + 2x` ...

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