Using the method of integration for parts show that ∫xe^(x/2) dx = 2xe^(x/2) - 4e^(x/2) + constant
You need to remember the formula of integration by parts such that:
`int udv = uv - int vdu`
Selecting `u = x ` and `dv = e^(x/2)dx` yields:
`u = x => du = dx`
`dv = e^(x/2)dx...
(The entire section contains 103 words.)
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