Using the method of integration for parts show that ∫e^x sin(x)dx = 1/2sin(x)e^x - 1/2cos(x)e^x + constant
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You should remember the formula of integration by parts such that:
`int udv = uv - int vdu`
Considering `u = sin x` and `dv = e^x dx` yields:
`u = sin x => du = cos x dx`
`dv = e^x dx => v = e^x`
`int e^x sin x dx = e^x sin x - int cos x e^x dx`
(The entire section contains 248 words.)
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