Using the method of integration for parts show that ∫e^x sin(x)dx = 1/2sin(x)e^x - 1/2cos(x)e^x + constant

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You should remember the formula of integration by parts such that:

`int udv = uv  - int vdu`

Considering `u = sin x`  and `dv = e^x dx`  yields:

`u = sin x => du = cos x dx`

`dv = e^x dx => v = e^x`

`int e^x sin x dx = e^x sin x - int cos x e^x dx`

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