# Using the method of integration for parts show that ∫e^x sin(x)dx = 1/2sin(x)e^x - 1/2cos(x)e^x + constant

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You should remember the formula of integration by parts such that:

int udv = uv  - int vdu

Considering u = sin x  and dv = e^x dx  yields:

u = sin x => du = cos x dx

dv = e^x dx => v = e^x

int e^x sin x dx = e^x sin x - int cos x e^x dx

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