Using the matrix transformation method, solve this system. 2x+6y-4z = 1 x+3y-2z = 4 2x+y-3z = -7
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Let us write the system as a matrix:
Let A be the matrix
2 6 -4 : 1
1 3 -2 : 4
2 y -3 : -7
We need to transform the matrix into the form :
1 0 0 : a
0 1 0 : b
0 0 1 : C
Where a , b, c is the solution to the system.
First we will divide R1 by 2:
==> 1 3 -2 : 1/2
1 3 -2 : 4
2 1 -3 : -7 R1 - R2
==> 1 3 -2 : 1/2
==> 0 0 0 : -3.5
2 1 -3 : -7
We notice that the second row has cancelled, then there are no solution to the system.
Also, when looking at the first 2 equations, we notice that the second is a multiply of the first but the answers are different. which is impossible.
Then, there are are no solutions to the system.
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