We have to find the value of lim x--> 1[ (x^2+11x-12)/(x-1)].
As substituting x = 0 gives us the indeterminate form 0/0, we can use l'Hopital's theorem and substitute the numerator and the denominator with their derivatives.
We get :
lim x--> 1 [2x + 11]
substitute x = 1
...
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We have to find the value of lim x--> 1[ (x^2+11x-12)/(x-1)].
As substituting x = 0 gives us the indeterminate form 0/0, we can use l'Hopital's theorem and substitute the numerator and the denominator with their derivatives.
We get :
lim x--> 1 [2x + 11]
substitute x = 1
=> 2 + 11
=> 13
The value of lim x-->1 [(x^2+11x-12)/(x-1)] = 13.