# Using the change of base formula how do I find the value of log 8 0.848 (logarithm)? Do not round until the final answer. Then round to four decimal places as needed.

*print*Print*list*Cite

Evaluate `log_8 0.848` :

If you can't remember the change of base formula, here is an approach to use. Let `log_8 0.848=x` .

Now rewrite in exponential form:

`8^x=0.848`

Take a logarithm of both sides. Which one? It really doesn't matter, except many scientific calculators only calculate log base 10 and log base e (the natural logarithm) so choose one of these.

`ln8^x=ln(0.848)` Use the power property of logs:

`xln8=ln(0.848)` Now divide:

`x=(ln(0.848))/(ln8)`

This, by the way, is the change of base formula. `log_b c=(lnc)/(lnb)=(logc)/(logb)=(log_k c)/(log_k b)` for any choice of natural number k>1.

----------------------------------------------------------------

`x=(ln0.848)/(ln8)~~-0.0793`

----------------------------------------------------------------

Check: `8^(-0.0793)~~0.84797874` or 0.848

You can apply this property of logarithm: `log_ba = loga/(logb).`

So, in your problem `log_8(0.848)`

a = 0.848 and b = 8. Applying the property, you have:

`log_8(0.848) = log(0.848)/(log8)`

Thus, the answer is -0.07928794337.

Rounding that off to four decimal places gives you -0.0793.