Using an air canon at 90 degrees, if you shoot an object 6 meters upward in 6.76 seconds, what is its velocity.
The air cannon is used to shoot an object upwards at 90 degrees to the horizontal. It takes 6.76 seconds to travel 6 m.
Use the formula relating distance, time, acceleration and time `s = u*t + (1/2)*a*t^2` where s is the distance traveled in time t if the initial velocity is u and the acceleration is a.
The values given in the problem are s = 6 m, t = 6.76 s, the acceleration is that due to gravity and equal to 9.8 m/s^2 in the downward direction; u has to be determined.
=> `6 = u*6.76 - (1/2)*9.8*6.76^2`
=> `u ~~ 34.01` m/s
The velocity with which the object is shot upwards is approximately 34.01 m/s
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