# Use simple math and compound interest to find the ending balance for \$3,000 at 8% over 2 years.

The ending balance of \$3,000 at an interest rate of 8% after 2 years is equal to \$3,480 if simple interest is applied, and it is equal to \$3,499.2 if compound interest is applied. A principal amount, at a rate of simple interest r per annum, after a time period t years increases to `P_f = P+P*t*r`

Compound interest refers to the situation where interest in any period is earned on both the principal and the interest earned in all the earlier periods. A principal amount P, at the rate of interest r per annum, after a time period t years increases to `P_f = P(1+r)^t`

In the problem, the principal P = \$3,000. The rate of interest is 8%, and the time period is 2 years.

The simple interest earned on \$3,000 in 2 years is equal to 3,000*0.08*2 = 480. The ending balance is equal to 3,000+480 = \$3480.

In the case of compound interest, the ending balance after 2 years would be 3,00o*(1+0.08)^2 = 3,499.2.

The ending balance of \$3,000 at an interest rate of 8% after 2 years is equal to \$3,480 if simple interest is applied, and it is equal to \$3,499.2 if compound interest is applied.

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