1 Answer | Add Yours
You should remember that `a<b` and `f(x) < g(x)` , then `int_a^b f(x) dx < int_a^b g(x) dx.`
Notice that 0<1 and you need to verify if `sqrt(1+x^2) < sqrt(1+x) ` over the interval [0,1] such that:
If `x in [0,1] => x^2 < x => x^2 + 1 < x + 1 => sqrt(x^2 + 1)<sqrt(x+1)`
Since `sqrt(x^2 + 1)<sqrt(x+1),` then you may use the property of integrals stated above such that:
`sqrt(x^2 + 1)<sqrt(x+1) => int_0^1 sqrt(x^2 + 1) dx < int_0^1 sqrt(x+1)dx`
Hence, using the properties of integrals yields that inequality `int_0^1 sqrt(x^2 + 1) dx < int_0^1 sqrt(x+1) dx` holds.
We’ve answered 319,199 questions. We can answer yours, too.Ask a question