Use linear approximation, i.e. the tangent line, to approximate 125.1^(1/3) as follows: Let f(x)=x^(1/3). The equation of the tangent line to f(x) at x=125 can be written in the form y=mx+b where m = b = Using this, we find our approximation for 125.1^(1/3) is ______

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Use a linear function to approximate `125.1^(1/3)` :

(1) Let `f(x)=x^(1/3)`

(2) We will find a linear approximation to f(x) at x=125.

(3) `f(125)=5`

(4) `f'(x)=(1/3)x^(-(2)/3)` . This is...

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