Use factoring and the zero product property to solve the following: z(z+1)(z+3)=0    

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`z(z+1)(z+3) = 0`

The above function is already in the factorized form with z,(z+1) and (z+3) as factors.

`f(x) = z(z+1)(z+3)`

Using zero product property to f(x) = 0 we need either;

`z = 0`

`(z+1) = 0`

`(z+3) = 0`

So the values of z that satisfy f(x)...

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`z(z+1)(z+3) = 0`

The above function is already in the factorized form with z,(z+1) and (z+3) as factors.

`f(x) = z(z+1)(z+3)`

Using zero product property to f(x) = 0 we need either;

`z = 0`

`(z+1) = 0`

`(z+3) = 0`

 

So the values of z that satisfy f(x) = 0 are;

z = 0

z = -1

z = -3

 

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