If you are plotting the points/line and demonstrating the slope on a graph, then the previous answer is correct. You can set up a table.
However, like the previous answer suggests, the equation must be in slope-intercept format, which is y=mx+b. Since you have x = -4y, you have to do a little simple algebra to flip it around.
If x= -4y
Divide by -4 on both sides.
You get x/-4 = y OR y=x/-4, which is now in slope-intercept format.
The slope (m) is found in front of x and since x/-4 is the same as -1/4x, then you have a slope of -1/4.
This can be seen in the previous post's table. When y (rise) equals -1/2, x (run) = 2. Rise/run = -1/2 /2, which also equals -1/4.
Basically, you can set up a table to solve for the y value. You pick the x value.
x | y
0 | 0
1 | -1/4
2 | -1/2
Then you can plot these points on your graph.
Using the slope-intercept formula: y = mx + b You can then determine the slope of the line. Remember rise/run.
The slope of a line ax + by + c = 0 is the rate at which y changes with respect to x.
The slope is given by the derivative `dy/dx` .
For the relation x = -4y, to determine the required slope, take the derivative of both sides with respect to x.
`dx/dx = (d(-4y))/dy`
`1 = -4*dy/dx`
`dy/dx = -1/4`
The required slope of the line x = -4y is -1/4