We have the functions f(x) = 3x+ 2 and g(x) = x^2 + 1
u = fog ( x) = f(g(x))
=> f(x^2 + 1)
=> 3(x^2 + 1) + 2
=> 3x^2 + 3 + 2
=> 3x^2 + 5
v = gof(x) = g(f(x))
=> g( 3x + 2)
=> (3x + 2)^2 +1
=> 9x^2 + 4 + 12x + 1
=> 9x^2 + 12x + 5
u' = 6x
v' = 18x + 12
Therefore u' is not equal to v'.
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