# Two tugboats pull a disabled supertanker. Each tug exerts a constant force of 1.50*10^6 N, one at an angle 15.0 degrees west of north, and the other at an angle 15.0 degrees east of north, as...

Two tugboats pull a disabled supertanker. Each tug exerts a constant force of 1.50*10^6 N, one at an angle 15.0 degrees west of north, and the other at an angle 15.0 degrees east of north, as they pull the tanker a distance 0.720 km toward the north. What is the total work done by the two tugboats on the supertankers?

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Two tugboats pull a disabled supertanker. Each tugboat exerts a constant force of 1.50 X 10^6 N, one at an angle 15.0 degrees west of north, and the other at an angle 15.0 degrees east of north, as they pull the tanker a distance 0.720 km toward the north.

The force exerted by each tugboat can be divided into two components: one of them towards the north and the other towards the east and the west. The components towards the west of the tugboat pulling in the direction 15.0 degrees west of north is equal to the component towards the east of the tugboat pulling in the direction 15.0 degrees east of north. These cancel out.

The other components add up to give a total of 2*1.5*10^6*cos 15 = 3*10^6*cos 15.

As the tanker is pulled for a distance 0.720 km towards the north, the product of the force and the distance it acts for is 720*3*10^6*cos 15 = 2086.3*10^6 J

**The total work done by the two tugboats is 559*10^6 J.**

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