According to the law of constant composition both samples should have equal mass ratios of O and N.

In sample one we have 2.602g of N and 6.4g of O.

Mass ratio

`N:O = 2.602/6.4`

For second sample also this mass ratio is applicable.

In the second sample we have 3.903g of N. Let us say we have xg of O.

Mass ratio

`N:O = 3.903:x`

`2.602/6.4 = 3.903:x`

`2.602x = 3.903xx6.4`

`x = 9.6`

*So from the second sample we get 9.6g of O.*

**Further Reading**

## We’ll help your grades soar

Start your 48-hour free trial and unlock all the summaries, Q&A, and analyses you need to get better grades now.

- 30,000+ book summaries
- 20% study tools discount
- Ad-free content
- PDF downloads
- 300,000+ answers
- 5-star customer support

Already a member? Log in here.

Are you a teacher? Sign up now