# In a two-person bobsled race, the first few seconds of the run are crucial. During a practise run on a flat ice surface,where the coefficient of...kinetic friction for the sled is 8.00 *10^-3, the...

In a two-person bobsled race, the first few seconds of the run are crucial. During a practise run on a flat ice surface,where the coefficient of...

kinetic friction for the sled is 8.00 *10^-3, the sled accelerates at 4.00m/s^2 (forward) when one person pushes with a force of 503N( forward) and the second person pushes with a force of 496N(forward). What is the mass of the empty sled?

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You are only allowed to ask one question at a time. I have edited your question in accordance with that.

The sled is being pushed by two people, one exerts a force of 503 N and the other exerts a force of 496 N. The total force exerted is 503 + 496 = 999 N.

If the mass of the sled is M, we can calculate the force of kinetic friction using the given coefficient of kinetic friction as M*8*10^-3.

The net force applied on the sled is 999 - M*8*10^-3

We see that the sled is accelerated at 4 m/s^2 due to the net force.

So 999 - M*8*10^-3 = M*4

=> 999 = M(4 + 8*10^-3)

=> M = 999/4.008

=> M = 249.25 kg

**The required mass of the sled is 249.25 kg**