Two balls of mass 3 kg one moving at 15 m/s and the other at 24 m/s collide with each other and are stuck. The combined mass moves at 12 m/s. What is the energy released as heat in the process.

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The total energy of a system is conserved. Each of the balls has mass 3 kg. Before their collision, the speed of one of them is 15 m/s and the speed of the other is 24 m/s.

The total kinetic energy of the system initially can be determined using the...

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The total energy of a system is conserved. Each of the balls has mass 3 kg. Before their collision, the speed of one of them is 15 m/s and the speed of the other is 24 m/s.

The total kinetic energy of the system initially can be determined using the formula for kinetic energy KE = (1/2)*m*v^2. Prior to their collision, the total energy in the system is (1/2)*3*15^2 + (1/2)*3*24^2 = 1201.5 J. After collision, the mass of the body is 3 + 3 = 6 kg and its speed is 12 m/s. The kinetic energy of the system is (1/2)*6*12^2 = 432 J

The difference in kinetic energy is released as heat. Here, it is equal to 1201.5 - 432 = 769.5 J

The energy released as heat in the process is 769.5 J

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