Two balls, each with a mass of 0.813 kg, exert a gravitational force of 8.38 x 10^-11 N on each other. How far apart are the balls? The value of the universal gravitational constant is 6.673 x 10^-11...
Two balls, each with a mass of 0.813 kg, exert a gravitational force of 8.38 x 10^-11 N on each other.
How far apart are the balls? The value of the universal gravitational constant is 6.673 x 10^-11 N m^2/kg^2. Answer in units of m
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The formula for gravitational attraction is
Fg = (Gm1m2)/r^2
In this formula, G is the Universal Gravitational Constant while m1 and m2 are the masses of the two bodies. R is the distance of separation between...
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Let the distance between the two balls be d and their masses be m1 and m2. Then by gravitational law, the force of attraction F,between them is:
F =G*m1*m2/d^2 .
By data,F = 8.38 *10^(-11)N, m1 = m2 = 0.813 kg , G =6.673 x 10^-11 N m^2/kg^2 and d is to be determined.
Therefore,
d =sqrt( G*m1*m2/F ). Substituting the values from data,
d = sqrt{(6.673 x 10^-11)(0.813)^2/(8.38*10^-11)}
=0.725486104 m is the required distance between the two masses, where the gravitational attractional force between them is as given.
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