# Two balls, each with a mass of 0.813 kg, exert a gravitational force of 8.38 x 10^-11 N on each other. How far apart are the balls? The value of the universal gravitational constant is 6.673 x 10^-11...

Two balls, each with a mass of 0.813 kg, exert a gravitational force of 8.38 x 10^-11 N on each other.

How far apart are the balls? The value of the universal gravitational constant is 6.673 x 10^-11 N m^2/kg^2. Answer in units of m

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The formula for gravitational attraction is

Fg = (Gm1m2)/r^2

In this formula, G is the Universal Gravitational Constant while m1 and m2 are the masses of the two bodies.  R is the distance of separation between...

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## Related Questions

neela | Student

Let the distance between the two balls be d and their masses be m1 and m2. Then by gravitational law, the force of attraction F,between them is:

F =G*m1*m2/d^2 .

By data,F = 8.38 *10^(-11)N,  m1 = m2 = 0.813 kg , G =6.673 x 10^-11 N m^2/kg^2 and d is to be determined.

Therefore,

d =sqrt( G*m1*m2/F ). Substituting the values from data,

d = sqrt{(6.673 x 10^-11)(0.813)^2/(8.38*10^-11)}

=0.725486104 m is the required distance between the two masses, where the gravitational attractional   force  between them  is as given.

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