In triangle ABC, A = 30°, C = 105°, a = 8. Find side b.

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In a triangle ABC, a/sin A = b/sin B = c/sin C

The angles of a triangle add up to 180 degrees.

A = 30 degrees and C = 105 degrees, this gives B = 180 - 30 - 105 = 45 degrees.

a/sin A = b/sin B

=> 8/sin...

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In a triangle ABC, a/sin A = b/sin B = c/sin C

The angles of a triangle add up to 180 degrees.

A = 30 degrees and C = 105 degrees, this gives B = 180 - 30 - 105 = 45 degrees.

a/sin A = b/sin B

=> 8/sin 30 = b/sin 45

=> b = 8*sin 45/sin 30

=> b = 8*2/sqrt 2

=> b = 8* sqrt 2

=> b = 11.31

The side b is 11.31

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