If a trapezoid has a top base of 6 and a bottom base of 30 and a height of 15, what is its area?

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The area of a trapezium with parallel sides of length a and b which are separated by a distance d is given by (1/2)*(a + b)*d.

Here, we have a trapezium with parallel sides of length 6 and 30 and the height which is also the distance separating the parallel sides as 15.

The area of the trapezium is 15*(6 + 30)/2

=> 15*36/2

=> 15*18

=> 270

The required area of the trapezium is 270.

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