A train, starting from rest from station A, travels along a straight horizontal track until it stops at station B, which is 2400 m from A. Initially, the train accelerates at a uniform rate of 0·4 ms–2 until it reaches a speed of 16 ms–1. It then maintains this speed of 16 ms–1 for T s, before decelerating uniformly to rest in 20 s.
Find the value of T.
Previous parts of the question are answered in;
Refer the attached image for the calculation.
It is given that the train has 2400. The area under the velocity time graph represent the travelled distance of the train.
Area under the velocity time graph` = (T+(40+T+20))/2xx16`
`(T+(40+T+20))/2xx16 = 2400`
`16(T+30) = 2400`
`T = 120`
So the value of T is 120 seconds.