A toy car runs off the edge of a table that is 1.621 m high. The car lands 0.3727 m from the base of the table. How long does it take for the car to fall? What is the horizontal velocity of the...

A toy car runs off the edge of a table that is 1.621 m high. The car lands 0.3727 m from the base of the table. How long does it take for the car to fall? What is the horizontal velocity of the car?

The acceleration due to gravity is 9.8 m/s^2.

Asked on by holyhenry

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justaguide | College Teacher | (Level 2) Distinguished Educator

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The height of the table from which the toy car runs off is equal to 1.621 m. The car lands 0.3727 m from the base of the table. As the car is moving horizontally, the vertical component of its velocity is 0. Let the time taken for the car to fall till the ground is equal to t. As the distance traveled in time t is 0.3727 m and the acceleration due to gravity is 9.8 m/s^2, we have 0.3727 = 0*t + 9.8*t^2

Solving for t gives t = 0.195 s.

As the car is able to travel a horizontal distance of 1.621 m in 0.195 seconds, its horizontal speed is 1.621/0.195 = 8.312 m/s

It takes the car 0.195 s to fall down and its horizontal velocity is 8.312 m/s.

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