# A tin can's diameter is 5 inches and it's height is two more than three times the diameter . Find the volume of the tin can.

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The volume of a cylinder with a base of area A and height h is A*h.

Here we have a can, the diameter of which is 5 inches. The area is equal to pi*(5/2)^2.

Its height is 2 more than three times the diameter or 2 + 3*5 = 17

The volume is pi*(5/2)^2*17

=> pi* 25*17 / 4

=>106.25*pi

**The required volume of the can is 106.25*pi cubic inches.**

Given that the diameter is 5 in.

The height = two more that 3 times the diameter.

==> h = 2 + 3*d = 2+ 3*5 = 2 + 15 = 17

Then the height = 17 in.

Now we need to find the volume.

We know that the volume of the cylinder is:

V = r^2 * pi *h where r is the radius and h is the height.

==> r = diameter/2 = 5/2 = 2.5

==> h= 17

==> V = (2.5)^2 * pi * 17 = 106.25*pi in^3

**Then, the volume of the can is 106.25*pi = 333.79 in^3 **

The diameter of the tin can = 5 in.

So the radius r of the tin can r = 5/2 in = 2.5 in.

The height h of the tin h = 2 more than 3times diameter = 2+3*5 = 17 in.

Therefore the volume v of the tin can v = pr^2*h = pi*(2.5^2)*17 c in

= 106.25pi inch^3 = 333.79 inch^3.

The tin can is a cylindrical container, so it's volume is:

V = (pi*r^2)*h

h is the height of cylinder

r is the radius = d/2

d is the diameter

The data from enunciation are:

d = 5 inches => r = 5/2 inches

h = 3d + 2

h = 3*5 + 2

h = 17 inches

The volume is:

V = pi* (5/2)^2*17