A tin can's diameter is 5 inches and it's height is two more than three times the diameter . Find the volume of the tin can.
Given that the diameter is 5 in.
The height = two more that 3 times the diameter.
==> h = 2 + 3*d = 2+ 3*5 = 2 + 15 = 17
Then the height = 17 in.
Now we need to find the volume.
We know that the volume of the cylinder is:
V = r^2 * pi *h where r is the radius and h is the height.
==> r = diameter/2 = 5/2 = 2.5
==> h= 17
==> V = (2.5)^2 * pi * 17 = 106.25*pi in^3
Then, the volume of the can is 106.25*pi = 333.79 in^3
The volume of a cylinder with a base of area A and height h is A*h.
Here we have a can, the diameter of which is 5 inches. The area is equal to pi*(5/2)^2.
Its height is 2 more than three times the diameter or 2 + 3*5 = 17
The volume is pi*(5/2)^2*17
=> pi* 25*17 / 4
The required volume of the can is 106.25*pi cubic inches.
The diameter of the tin can = 5 in.
So the radius r of the tin can r = 5/2 in = 2.5 in.
The height h of the tin h = 2 more than 3times diameter = 2+3*5 = 17 in.
Therefore the volume v of the tin can v = pr^2*h = pi*(2.5^2)*17 c in
= 106.25pi inch^3 = 333.79 inch^3.
The tin can is a cylindrical container, so it's volume is:
V = (pi*r^2)*h
h is the height of cylinder
r is the radius = d/2
d is the diameter
The data from enunciation are:
d = 5 inches => r = 5/2 inches
h = 3d + 2
h = 3*5 + 2
h = 17 inches
The volume is:
V = pi* (5/2)^2*17