`(root(4)(16+h)-2)/h`
function `f(x)=root(4)(x)`
evaluate at a=16
`f(16+h)=root(4)(16+h)`
`f(16)=root(4)(16)=2`
`(f(16+h)-f(16))/h=(root(4)(16+h)-2)/h`
So the answer is `f(x)=root(4)(x)` and `a=16`
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