According to the circuit, shown in the attached picture,
Current through `R_4` = Current through `R_3` + Current through `R_5`
So, `I_R_4` = 0.18153 A
Again, voltage through `R_5` =(current through `R_5` )*`R_5`
Thus, `V_R_5=-0.375 ` V.
Negative value of voltage means current flow will be in the opposite direction, which is indeed the case for R5.