# In a thermomtr upper & lower fixed points were err marked. 100 instead of 105 & 0 inst of -5. What r correct temp corresponding to 40 & 80?

*print*Print*list*Cite

We need to define a transformation between the false scale indication and the real temperature on a correct Celsius scale.

The real extent of the incorrect scale is

`Delta(T) = 105 -(-5) =110 degree C`

The length of incorrect scale is

`L =100-0 =100 units`

The real temperature for 40 units on the incorrect scale is

`T_1 = L_1*(Delta(T))/L = 40*110/100 =40*1.1 =44 Celsius `

The real temperature for 80 units on the incorrect scale is

`T_2 =L_2*(Delta(T))/L =80*110/100 =80*1.1 =88 Celsius`

**Answer: The correct temperatures corresponding to 40 and 80 are 44 and 88 degree Celsius**

if u have err marked only end points and other points are correct then there will be no difference 40 would be taken 40 and same for 80

but

if dibvisions other than end points are also err marked then 40 would correspond 35

and 80 would correspond 75