There are two containers filled with gases.In both containers,gases are same temperature and pressure.The first container is 3 L and contains 0.9 moles of gases. The second container is 1 L.How many moles of gas are there in the second container?
- print Print
- list Cite
Expert Answers
calendarEducator since 2012
write1,657 answers
starTop subjects are Math, Science, and Social Sciences
This can be done by ideal gas law PV = nRT.
Let;
n1 = moles in gas 1 = 0.9
n2 = moles in gas 2
`R = 8.314`
`V1 = 3L`
`V2 = 1L`
For both cases pressure and temperature is same.And R is also same for both gases.
`PV = nRT`
`P/(RT) = n/V`
Since P/(RT) is same for both;
`(n1)/(V1) = (n2)/(V2)`
`n2 = (n1V2)/(V1)`
`n2 = 0.9*1/3`
`n2 = 0.3`
So in the other gas there are 0.3 moles.
Assumption
- Both gasses act as ideal gasses.
Related Questions
- There are two containers filed with gases.In both containers,gases are the same temperature and...
- 1 Educator Answer
- a mole of hydrogen atoms contains 6.02x10^23 atoms and occupies 22.4 L. How many hydrogen atoms...
- 1 Educator Answer
- What are the layers of the atmosphere and the gases in each layer? What is the weight of each gas...
- 1 Educator Answer
- What is the reason octane (C8H18) is a liquid at room temperature while methane (CH4) is a gas at...
- 1 Educator Answer
- One mole of Argon gas is confined to a `1.0 L` container at a pressure of `10 atm` . What is the...
- 1 Educator Answer
calendarEducator since 2012
write1,284 answers
starTop subjects are Math and Science
To solve for the number of moles of gas in the second container, apply Ideal Gas Law. The formula is:
`PV = nRT`
where P - pressure , V - volume , T - temperature, n - number of moles and R - universal constant (R=8.3145J / mol K ).
The given in the first conatiner are V = 3L and n=9 moles. Substitute these to the formula above.
`P_1(3) = 0.9 (8.3145)T_1`
Then, isolate `P_1` and `T_1` since their values are unknown.
`P_1/T_1 = (0.9(8.3145))/3`
`P_1/T_1 = 2.49435`
And in the second container, the given is V=1 L. Substitute this to the formula of Ideal Gas Law.
`P_2(1)=n(8.3145)T_2`
Isolate `P_2` and `T_2` too.
`P_2/T_2 = (8.3145n)/1`
`P_2/T_2 = 8.3145n`
Note that the pressure and temperature of the gases inside the two containers are the same. So,
`P_1/T_1 = P_2/T_2`
`2.49435=8.3145n`
Then divide both sides by 8.3145 to solve for n.
`2.49435/8.3145=(8.3145n)/8.3145`
`n =0.3`
Hence, there are 0.3 moles of gases in the second container.