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Sorry. There is a small error in reasoning in the earlier response. Dividing 6 different types of sweets equally between two children involves creating 2 packs with 3 sweets each. The number of ways this can be done in is `6C3 = (6!)/(3!(6-3)!) = (6!)/(3!*3!) = 20`
The 6 sweets can be divided equally among the two children in 20 different ways.
There are six sweets each with a different flavor that have to be divided equally between 2 children.
Consider the number of ways in which 3 of the sweets can be given to the first child. There are 6 options for the first sweet, 5 options for the second sweet and 4 options for the third sweet. The total number of ways in which the sweets can be divided is 6*5*4 = 120
The sweets can be divided between the two in 120 different ways.
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