There are 3 different possible structures (known as isomers) for a dibromoethene molecule, C2H2Br2. (FULL QUESTION BELOW)
There are 3 different possible structures (known as isomers) for a dibromoethene molecule, C2H2Br2. One of them has no net dipole moment, but the other two do. Draw a Lewis structure for each isomer. Include H atoms
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dibromo methane has indeed three isomers. in order to classify them it is a good thing to draw their lewis structure.
H Br . l l . C= C has a net dipole . l l . H Br
H H . l l . C= C has a net dipole . l l . Br Br
Br H . l l . C= C has NO net dipole . l l . H Br
The trans-1,2-Dibromoethene has no net dipole because the charge that the bromine is exhibiting cancels out as compared to the other two isomers where there is unbalanced charged due to the positions of bromine.
hope this helps :)
*note: the bonds between C-H and C-Br are slanted.
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