There are 2 boxes one of them is 4•4•4 and the other is 12•12•12 how many times is the surface area of the larger cube?
Let x = the length of small cube's sides = 4
Let y= the length of the large cube's sides = 12
The formula for the surface area of a cube is as follows:
`SA = 6a^2` , where a is the length of each side
We wish to know how many times larger the surface area of the bigger cube is of the smaller cube:
`n = (6y^2)/(6x^2)`
Therefore, the surface area of the larger cube is 9 times bigger than the smaller cube.