Th sum of three consecutive multiples of 5 is 120. Find the three integers.

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hala718's profile pic

hala718 | High School Teacher | (Level 1) Educator Emeritus

Posted on

Let the first number be X

Then the second number is x+ 5

Then the third number is x+ 10

Now we are given that the sum of the three terms is 120.

==> x + x+ 5 + x+ 10 = 120

==> 3x + 15 = 120

Now we will subtract 15 .

==> 3x = 105

Now we will divide by 3.

==> x = 35

Then the numbers are: 35, 40 , and 45.

giorgiana1976's profile pic

giorgiana1976 | College Teacher | (Level 3) Valedictorian

Posted on

The consecutive integers, multiples of 5 are:

5x , 5x + 5 , 5x + 10

We'll sum the terms:

5x + (5x + 5) + (5x + 10) = 120

We'll combine like terms:

15x + 15 = 120

15(x+1) = 120

We'll divide by 15:

x + 1 = 8

x = 8 - 1

x = 7

The consecutive integers, multiple of 5, are: 35 ; 40 ; 45.

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