# Tanx = 3/2, cosx<0, based on this information, secx=?

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`tan x=3/2`

This means the ratio of opposite to the adjacent side of a right triangle is 3/2, hence we can find the hypotenuse.

hypotenuse=`sqrt(3^2+2^2)=sqrt(13)`

Since the cosx is negative then `cosx=-2/sqrt(13)`

`secx=1/cosx=-sqrt(13)/2`