The tangent from (1,8) is tangential to the circle x^2 + 2x + y^2 + y + 1 = 0 at what point?

Expert Answers

An illustration of the letter 'A' in a speech bubbles

A line drawn from (1, 8) is supposed to be tangential to the circle x^2 + 2x + y^2 + y + 1 = 0

The equation of the tangent is given by (y - 8) = m(x - 1) where m has to be determined

=> y - 8 - xm + m = 0

=> y = mx - m + 8

substitute in the equation of the circle

x^2 + 2x + (mx - m + 8)^2 + mx - m + 8 + 1 = 0

=> x^2 + 2x + m^2x^2 + (m - 8)^2 + 2mx(8 - m) + mx - m + 9 = 0

=> x^2(1 + m^2) + x(2m(8-m) + 2 + m) + (m - 8)^2 - m + 9 = 0

As the tangent touches the circle only at a single point

(2m(8-m) + 2 + m)^2 = 4(1 + m^2)((m - 8)^2 - m + 9)

This is a very complex equation and has been solved using an online equation solver to get the roots:

m = (68 - 4*sqrt 19)/15 and m = (68 + 4*sqrt 19)/15

The equations of the tangents are: (y - 8)/(x - 1) = (68 - 4*sqrt 19)/15 and (y - 8)/(x - 1) = (68 + 4*sqrt 19)/15

Approved by eNotes Editorial Team
Soaring plane image

We’ll help your grades soar

Start your 48-hour free trial and unlock all the summaries, Q&A, and analyses you need to get better grades now.

  • 30,000+ book summaries
  • 20% study tools discount
  • Ad-free content
  • PDF downloads
  • 300,000+ answers
  • 5-star customer support
Start your 48-Hour Free Trial