Solve `tan(x)+sqrt(3)=0 ` :

`tan(x)+sqrt(3)=0 `

`tan(x)=-sqrt(3) `

`x="Tan"^(-1)(-sqrt(3))`

The tangent has value `sqrt(3) ` when the sine has value `sqrt(3)/2 ` and the cosine has value `1/2 ` . (`tanx=sinx/cosx ` )

The tangent is positive in the first and third quadrants, and negative in the second and fourth quadrants.

Thus `x=-pi/3+npi ` for ` ``n in ZZ ` (n an integer.)

The graph of tan(x) and the line `y=-sqrt(3) ` :

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