If tan x = 3/4 and tan b = 2/7 Find tan(a-b)

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hala718's profile pic

hala718 | High School Teacher | (Level 1) Educator Emeritus

Posted on

tana = 3/4       tan b = 2/7

We know that:

tan(a-b) = (tan a - tanb)/(1+ tana*tanb)

Let us substitute:

tan(a-b) = (3/4 - 2/7) / [1+ (3/4)*(2/7)]

               = (21-8)/28 / (1+ 6/28)

                = 13/28 / (34/28)

                 = 13/34

==> tan(a-b) = 13/34

william1941's profile pic

william1941 | College Teacher | (Level 3) Valedictorian

Posted on

We know that tan(a-b) = ( tan a -tan b)/ (1 +tan a* tan b)

Using tan a = 3/4 and tan b = 2/7

tan(a+b) = ( tan a -tan b)/ (1 +tan a* tan b)

=> ( 3/4 - 2/7) / ( 1 + (2/7)*(3/4))

=> (21/28 - 8/28) / (28/28 + 6/28)

=> 13 / 34

Therefore  tan(a –b) = 13/34

lochana2500's profile pic

lochana2500 | Student, Undergraduate | (Level 1) Valedictorian

Posted on

tan (a-b)

= (tan a - tan b)  / (1 + tan a.tan b)

We know that : tan a = 3/4, tan b = 2/7

= (3/4 - 2/7) / [1 + (3/4)*(2/7)]

= (13/28) / (34/28)

= 13/34 

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