`tan(pi/4 - theta) = (1 - tan(theta))/(1 + tan(theta))` Prove the identity.

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`tan(pi/4-theta)=(1-tan(theta))/(1+tan(theta))`

we will use the following formula to prove the identity,

`tan(A-B)=(tanA-tanB)/(1+tanAtanB)` 

LHS=`tan(pi/4-theta)`

`=(tan(pi/4)-tan(theta))/(1+tan(pi/4)tan(theta))`

plug in the value of tan(pi/4)=1,

`=(1-tan(theta))/(1+tan(theta))`

LHS=RHS, Hence proved.

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