`(tan^2(theta))/sec(theta) = sin(theta)tan(theta)` Verfiy the identity.

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Chapter 5, 5.2 - Problem 17 - Precalculus (3rd Edition, Ron Larson).
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hkj1385 | (Level 1) Assistant Educator

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L.H.S

`(tan^2(theta))/sec(theta) = tan^2(theta)*cos(theta) = tan(theta)*cos(theta)*{tan(theta)} =`

`tan(theta)*cos(theta)*{sin(theta)/cos(theta)} = tan(theta)*sin(theta) = ` R.H.S

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