T is directly proportional to r². It is given that T=9 for a particular value of r. Find the value of T when this value of r is doubled.

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Mathematically, if T is directly proportional to r squared, we write that as:

T∝r^2

To get from a proportional expression (∝) to an equation (=), we have to add a multiplication factor to r^2 to account for the how fast T changes with respect to r^2, so:

T=k*(r)^2 (1)

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Mathematically, if T is directly proportional to r squared, we write that as:

T∝r^2

To get from a proportional expression (∝) to an equation (=), we have to add a multiplication factor to r^2 to account for the how fast T changes with respect to r^2, so:

T=k*(r)^2 (1)

From here, we can plug in the numbers we know, which leads to:

9=k*(r)^2 (2)

And understanding that r doubling is the same as 2*r,

T=k*(2*r)^2 (3)

Using the distributive property we get:

T=k*(2)^2*(r)^2 (4)

Which simplifies to:

T=4*k*(r)^2 (5)

Now, if we look to work we did up above in equation (2), we see that:

k*(r)^2=9 (6)

So, now we substitute 9 into equation (5) and get:

T=4*9=28,

So, T=28 when r is doubled.

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