`a(t) = 3cos(t) - 2sin(t), s(0) = 0, v(0) = 4` A particle is moving with the given data. Find the position of the particle.
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You need to remember the relation between acceleration, velocity and position, such that:
`int a(t)dt = v(t) + c`
`int v(t) dx = s(t) + c`
You need to find first the velocity function, such that:
`int (3cos t - 2sint )dt = int 3cos t dt - int 2sin t dt`
`int (3cos t - 2sint )dt = 3sin t + 2cos t + c`
The problem provides the...
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Integrate a(t) to get v(t)
`v(t) = 3 sin (t) + 2 cos (t) + C `
Use `v(0) = 4` to find C
`4 = 3 sin (0) + 2 cos (0) + C `
`C = 2 `
Thus,
`v(t) = 3 sin (t) + 2 cos (t) + 2 `
Integrate again: v(t) to get s(t)
`s(t) = -3 cos (t) + 2 sin (t) + 2t + c `
Use ` v(0) = 4` to find c
`0 = -3 cos (0) + 2 sin (0) + 2(0) + c `
`c = 3 `
Thus,
`s(t) = -3 cos (t) + 2 sin (t) + 2t + 3`
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