You need to solve the equation f'(x) = 0 to find the critical values of the function such that:

`f'(x) = (1/3)*x^(1/3 - 1)*((x+3)^(2/3)) + (2/3)x^(1/3)*(x+3)^(2/3-1)`

`f'(x) = (1/3)*x^(-2/3)*((x+3)^(2/3)) +...

(The entire section contains 95 words.)

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