If `a` is the length of one of the square sides and `l` is the length of the package, we have that the required girth `G` satisfies

` ``G = l +4a`

We want the girth to be as big as possible as this will lead to a bigger volume, so we have that `G=275` (the maximum girth allowed).

The volume `V` of the package satisfies

`V = la^2`

To maximise `V` with respect to `G = 275` we use the method of Lagrange multipliers

This involves solving the simultaneous equations

1) `(del V)/(del l) - lambda(delG)/(del l) = 0`

2) `(delV)/(dela) -lambda(delG)/(dela) = 0`

for `lambda`, subject to the constraint `G=275`

Now we have

1) `a^2 - lambda(1) = 0`

2) `2al - 4lambda = 0`

` ` 1) `implies` `a^2 = lambda` `implies` `a=sqrt(lambda)`

Substituting into 2) we get

2) `2lsqrt(lambda) -4lambda = 0` `implies` `l = (4lambda)/(2sqrt(lambda)) = 2sqrt(lambda)`

Considering the constraint `G = l +4a = 275` we have that

`2sqrt(lambda)+4sqrt(lambda) = 275`

`implies` `sqrt(lambda) = 275/6`

Therefore `a=275/6` and `l = 275/3` to give maximum volume `V=la^2`

**a = 45.833, b = 91.667**