# ʃ(superscript 2)(subscript -1) 3x^2dx

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### 1 Answer

This integral is using the power law for polynomials `int x^n dx=1/{n+1}x^{n+1}` for all `n ne -1` .

This means that the integral becomes

`int_{-1}^2 3x^2 dx` use power law

`=(3 1/3 x^3)_{-1}^2` cancel out the 3s

`=2^3-(-1)^3` simplify

`=8+1`

`=9`

**The integral is 9.**