If n represents the smaller of these two integers, which is an equation that can be used to find n? The sum of two consecutive even integers is 294.
The sum of two consecutive even numbers is 294. If the smaller number is n, the larger number is n + 2. To determine n, solve the equation n + n + 2 = 294 for n.
Or 2n + 2 = 294
n = 146
The equation to be solved to determine n is 2n + 2 = 294
As n is the smaller of the two consective even integers, therefore the second integer is n+2.
Sum of the two numbers is n + n+2 which is also equal to 294
So the equation to be used to fine the numbers is: n+n+2 = 294
which reduces to 2n+2 =294
The required equation is 2n+2 = 294 to find n.
The above equation yields n= 146 and the two integers are 146, 148
Since the smaller number is "n" and the larger number is a consecutive even version, then the larger number would be "n+2"
So the equation would be
and then you simplify to get the answer...like this:
Given :- sum of the two even intefers = 294 and
The smaller of the two integer is n
The larger integer = n + 2 [ enen numbers differ by 2 ]
since sum of these two even integer = 294
That is, n + n + 2 = 294
=> 2n + 2 = 294
=> 2(n + 1) = 294
=> ( n + 1)= 294/2 = 147
=> n + 1= 147
=> n = 146 <-- Answer